2x^2+(2t+1)x+t=0

Solution for 2x^2+(2t+1)x+t=0 equation:

Simplifying
2x2 + (2t + 1) * x + t = 0

Reorder the terms:
2x2 + (1 + 2t) * x + t = 0

Reorder the terms for easier multiplication:
2x2 + x(1 + 2t) + t = 0
2x2 + (1 * x + 2t * x) + t = 0

Reorder the terms:
2x2 + (2tx + 1x) + t = 0
2x2 + (2tx + 1x) + t = 0

Reorder the terms:
t + 2tx + 1x + 2x2 = 0

Solving
t + 2tx + 1x + 2x2 = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-1x' to each side of the equation.
t + 2tx + 1x + -1x + 2x2 = 0 + -1x

Combine like terms: 1x + -1x = 0
t + 2tx + 0 + 2x2 = 0 + -1x
t + 2tx + 2x2 = 0 + -1x
Remove the zero:
t + 2tx + 2x2 = -1x

Add '-2x2' to each side of the equation.
t + 2tx + 2x2 + -2x2 = -1x + -2x2

Combine like terms: 2x2 + -2x2 = 0
t + 2tx + 0 = -1x + -2x2
t + 2tx = -1x + -2x2

Reorder the terms:
t + 2tx + x + 2x2 = -1x + x + -2x2 + 2x2

Combine like terms: -1x + x = 0
t + 2tx + x + 2x2 = 0 + -2x2 + 2x2
t + 2tx + x + 2x2 = -2x2 + 2x2

Combine like terms: -2x2 + 2x2 = 0
t + 2tx + x + 2x2 = 0

The solution to this equation could not be determined.